Math, asked by Charlysingh, 1 year ago

с. S=4/3πsin 3t + 4/5πcos 5t

find the derivative of the function

Answers

Answered by pal69
6

s=4/3πsin3t +4/5πcos5t

ds/dt=4/3.π×3×cos3t +4/5.π×5×(-sin5t)

=4/π{cos3t-sin5t}

hope it's help u..✌✌✌✌✌


Charlysingh: it is wrong answer.
pal69: what is right ans
Charlysingh: 4/π(cos3t-sin5t)
pal69: ok
pal69: i did not understand in yput question
Charlysingh: 4/3π sin3t+4/5π cos5t
Answered by apurvavaishali524
0

Answer:

ds/dt=[4/3π ×3{d(sin t)}/dx]+[4/5π×5{d(cos t)}/dx

Step-by-step explanation:

4/π{cos3t-sin5t}

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