Question

Any one have no knowledge to solve it

Answer 1

hey there!!!

Solution:

let the original speed be xkm/ hr and original time be y hrs.

we know,

distance= speed × time

= x× y= xy.....distance.

according to the first condition,

(x+10)(y-2)= xy

xy-2x+10y-20= xy

2x-10y=-20.....(1)

according to the second condition,

(x-10)(y+3)= xy

xy+3x-10y-30= xy

3x-10y= 30........(2)

now,

subtracting (1) from(2),

3x-10y= 30

-2x+10y= 20

x =50

hence,

x= 50 km/hr.

now,

substituting value of x in (1),

2x-10y=-20

2(50)-10y=-20

100-10y= -20

-10y= -20-100

-10y= -120

y=-120/-10=12

hence,

original time = 12 hrs

now,

distance= x×y= 50× 12= 600 km

hope this helps!!☺✌❤