S=43.4%
C=11.3%
O=43.3%
calculate the empirical formula
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Hi there,
Given
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S percentage = 43.4
S atomic mass = 33
C percentage = 11.3
C atomic mass = 12
O percentage = 43.3
O atomic mass = 16
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☆ Calculate number of moles (n) by dividing element persentage over atomic mass
n(S) = 43.4 ÷ 32 = 1.356 mol
n(C) = 11.3 ÷ 12 = 0.94 mol
n(O) = 43.3 ÷ 16 = 2.7 mol
☆ Calculate mol ratio by dividing all moles over the lowest mol value which is 0.94
S ratio is 1.5
C ratio is 1
O ratio is 2.9~ 3
☆ To correct the fraction myltipl2 by 2
☆ The empirical formula is
《S3C2O6 》
♡ Hope the answer is helpful
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