Math, asked by Yuvrajreddykolli, 1 month ago

S 5. A right circular cylinder having diameter 12 cm and height 15 cm is full of ice-cream. The ice-cream is to be filled in cones of height 12 cm and diameter 6 cm having a hemispherical shape on the top. Then the number of such cones which can be filled with ice-cream is
a.9
b.8
c.10
d11​

Answers

Answered by Firdhous
1

Answer:

c

Step-by-step explanation:

The crt answer of this question is option C

Answered by ram621
1

For right circular cylinder

Diameter = 12 cm

Radius(R1) = 12/2= 6 cm & height (h1) = 15 cm

Volume of Cylindrical ice-cream container= mr1²h1= 22/7 x 6x6x 15=11880/7 cm³

Volume of Cylindrical ice-cream container=11880/7 cm³

For cone,

Diameter = 6 cm

Radius(r2) =6/2 = 3 cm & height (h2) = 12 cm Radius of hemisphere = radius of cone= 3 cm

Volume of cone full of ice-cream- volume of cone + volume of hemisphere

=% mr2²h2 + % mr2³= π (12³h2 +212³)

= ½ * 22/7 (37× 12 + 2× 3³)

=% * 22/7 (9x12 + 2 × 27)

= 22/21 (108 +54)

= 22/21(162)

= (22×54)/7

Let n be the number of cones full of ice cream.

Volume of Cylindrical ice-cream container=n x Volume of one cone full with ice cream

11880/7 = n* 1188/7

11880 = n * 1188

n = 11880/1188=10

n = 10

Hence, the required Number of cones = 10

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