Question

S.
500 mL of a glucose solution contains 6.02 x 1022
molecules. The concentration of the solution is
(A) 0.1 M
(B) 1.0 M
(C) 0.2 M
(D) 2.0 M​

Answer 1

Answer:

0.2M

Explanation:

Use mole concept

1 mole = 6.02 * 10^23 molecules

6.02 *10^22 molecules = 0.1 mole

Volume = 500/1000 L

Molarity = no of moles / Volume in litre

0.1*2 =0.2 M

Hope it helps; -)