Question

S. A can do a piece of the work in s days and B can do some mort in 12 days . A worked A alone for 2 days and B for 3 days In 2 mary days will the remaining work be completed if they work together.​

Answer 1

Answer:

Given A takes 12 days to finish the work alone.

In 1 day he does 1/12 of the work.

Suppose B takes 20 days to do the work alone.

In 1 day B does 1/20 of the work.

In 1 day A and B together can do 1/12 + 1/20 = 8/60 = 2/15 of the work

They do work together for 3 days.

So in 3 days they can finish 3(2/15) = 2/5 of the work.

Portion of the work unfinished = 3/5 which has to be done by B.

To do 1/20 of the work B requires 1 day.

So to do 3/5 of the work B takes (3/5)/(1/20) = 12 days

Step-by-step explanation:

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