Question

S-
A taxi fare in a City first 3km, the
rupee 20 & for the destance 5 per km
distance Covered as x km and total
fare as y, write a linear eqation!​

Answer 1

Answer:

pleas upload full question

Answer 2

Answer:

5x - y + 5 = 0

Step-by-step explanation:

• Total distance = x km, for first 3km rupee = 20
• Then remaining distance = (x - 3) km and fare is 5 rupee per km, then fare of remaining distance = (x - 3)5
• Now total fare = y = 20 + (x - 3)5

This implies that, 5x - y + 5 = 0

Hence the required equation.

I hope it will help you. Thank you