Question

s and t are point on side PR and QR of ∆pqr such that <p=RTS show that ∆RPQ~∆RTS​

Answer 1

Answer:

Solution:

Given: angleP = angleRTS

To Prove:∆RPQ ~ ∆RTS

Proof: In ∆RPQ and ∆RTS

angle R = angle R. (common)

angle P = angle RTS (Given)

By AA similarity,

∆RPQ ~ ∆RTS

Hence,proved.

Step-by-step explanation:

Answer 2

$\huge{\mathfrak{\purple{Question}}}$

Sand T are points on sides PR and QR of PQR such that P=RTS . Show that RPQ - RTS.

$\huge{\mathfrak{\purple{Answer}}}$

In △RPQ and △RTS

∠R is common

∠RTS=∠P (Given)

∠PRQ=∠TRS=∠R (Common)

Hence, By AA criterion of similarity, △RPQ∼△RTS  

Hence proved