Question

S and T are points on sides PR and QR of ∆PQR such that angle P =angle RTS show that∆RPQ~ ∆RTS​

Answer 1

Answer:

In △RPQ and △RTS

 ∠RTS=∠P (Given)

∠PRQ=∠TRS=∠R (Common)

Hence, By AA criterion of similarity, △RPQ∼△RTS  [hence proved]

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Answer 2

Step-by-step explanation:

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