Question

S
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Find the smallest 4 digit number such that
when it is divided by 12, 18, 21 and 28. It
leaves remainder 3 in each case.
(a) 1011 (b) 1021 (C) 1031 (d) 2011​

Answer 1

Answer:

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Answer 2

Answer: 1011 (a)

Step-by-step explanation:

The required number is 1011.

Explanation:

Since  , 12 = 2 x 2 x 3

18 = 2 x 3 x 3

21 = 3 x 7

28 = 2 x 2 x 7

Least common multiple of 12, 18, 21 and 28 =   2 x 2 x 3 x 3x 7 =252

252 x 2 = 504

252 x 3 =756

252 x 4= 1008

Thus, the smallest 4 digit number such that when it is divided by 12, 18, 21 and 28 is 1008.

Also, the required no. leaves remainder 3.

So , the required number = 1008+3 = 1011

Hence, the required number is 1011.