Question

ǫᴜᴇsᴛɪᴏɴ :-

Find the area of the segment PQR of a circle with centre O, if the radius OR of a circle is 7 cm and the angle POR = 30°.
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sᴘᴀᴍ ᴀʟʟᴏwᴇᴅ ☑️​

Answer 1

$\huge\mathfrak\red{Answer}$

$= 13.08 {cm}^{2}$

$\huge\mathfrak\red{explaination}$

Area of the  segment AXB = Area of the sector OAXB − Area of triangle OAB.

The triangle OAB is an equilateral triangle since the length of sides are equal to the radius of the circle  and an angle is 600

Area of an equilateral triangle with length of side

a =√3 / 4 a square

Area of a sector of a circle of radius 'r' and angle

∅= ∅

360

Hence, Area of segment AXB 

$60 \div 360 \times 3.14 \times {12}^{2} = 75.36 - 62.28 = 13.08$

$answer = 13.08 {cm}^{2}$

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