Question

s) Find the zeros of the polynomial x²-4X+3.​

Answer 1

Step-by-step explanation:

Given, p(x)=x

2

−4x+3

=x

2

−3x−x+3

=x(x−3)−1(x−3)

=(x−3)(x−1)

For zeroes of polynomial, p(x)=0

i.e. (x−3)(x−1)=0

or, x=3 or x=1

Let, α=3 and β=1

α+β=

a

−b

αβ=

a

c

Here, a=1b=−4c=3

α+β=4

αβ=3

Answer 2

Answer:

x = 1,3

Step-by-step explanation:

=>x^2 - 4x +3

=> x^2 -3x -x +3

=> x ( x-3 ) - ( x-3 )

=>( x-3 ) ( x-1 )

=>x= 3,1

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