Question

S. In the figure, 'O' is the centre of the circle.
OM=3cm and AB - 8cm. Find the radius of
the circle​

Answer 1

Given o is the center of circle ,OM=3 cm and AB=8 cm

Join O to A and B

In figure OM show that the perpendicular from center O on cord AB

WE know that Perpendicular from the Center of a Circle to a Chord Bisects the Chord.

Then AM=BM

So AM=BM=\frac{AB}{2}=\frac{8}{2}=4 cmAM=BM=

2

AB

=

2

8

=4cm

\Delta AOMΔAOM

(AO)^{2}=(AM)^{2}+(OM)^{2}=(4)^{2}+(3)^{2}=16+9=25(AO)

2

=(AM)

2

+(OM)

2

=(4)

2

+(3)

2

=16+9=25

\Rightarrow AO=5 cm⇒AO=5cm

Pls mark as the brainliest answer.