Physics, asked by nishajohn4197, 10 months ago

s.
In the given circuit, the effective resistance between points A and C will be


Attachments:

Answers

Answered by kaushik05
26

hope this helps you ☺️☺️☺️

Attachments:
Answered by abhijattiwari1215
3

Answer:

The effective resistance between points A and C is ⅔R .

Explanation:

  • If n number of resistance are connected end to end so that same current flows through each one of them then, they are said to be in series combination.
  • The equivalent resistance in series combination is

R(eq) = R1+ R2 + R3 + ... + Rn

  • If n number of resistances are connected in between two common points so that each of them provide a separate path for current, then then they are said to be in parallel combination.
  • The equivalent resistance in parallel combination is

 \frac{1}{R(eq)}  =  \frac{1}{R1}  +  \frac{1}{R2}  + ... \frac{1}{Rn}

In given circuit:

  • Resistances between path ADC are connected in series.
  • Resistances between path ABC are connected in series.
  • Resistance ADC, ABC and AC are connected in parallel.
  • Resistance between path ADC is given by

R(ADC) = R + R = 2R

  • Resistance between path ABC is given by

R(ABC) = R + R = 2R

  • Resistance between path AC is 2R.
  • Now, equivalent resistance between point A and C is given by parallel combination of all the three path resistances.

 \frac{1}{R(eq)}  =  \frac{1}{2R}   +  \frac{1}{2R}  +  \frac{1}{2R}  \\\frac{1}{R(eq)}  =  \frac{3}{2R}  \\  R(eq)=  \frac{2}{3} R

  • Hence, equivalent resistance between points A and C is ⅔R .
Similar questions