(x-5) is factor of x cude+3x sq.+ky-10 find the value of k
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Answer:
Value of k = 11
Step-by-step explanation:
Factor Theorem:
" If (x-a) is a factor of a polynomial p(x) then p(a) = 0"
Here ,Let p(x) = 3x²+kx+6if (x+3) is a factor of p(x)
then p(-3) = 0=> p(-3) = 3(-3)²+k(-3)+6 = 0
=> 27-3k+6 =0
=> -3k+33=0
=> -3k = -33
Divide both sides by (-3),
we get=> k = 11
Therefore,Value of k = 11
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