Question

'S' is an infinite set of odd natural
numbers. What percentage of the
numbers of 'S' are divisible by both 5 and 3?

Answer 1

Answer:

0.0825

Step-by-step explanation:

this is what I can tell

most certainly right

Answer 2

Given :  'S' is an infinite set of odd natural numbers.

To Find :  What percentage of the numbers of 'S' are divisible by both 5 and 3?

Solution:

divisible by both 5 and 3 means divisible by 15

1  3  5  7  9  11 13  15   -  (  1 number if divisible out of  8)

17 , 19 , 21  , 23 , 25 , 27 , 29 , 31 , 33 , 35 , 37 , 39 , 41 , 43 , 45   (    1 number if divisible out of  15)  

and so on  1 is divisible out of  each next 15  

Hence  n + 1  numbers  are divisible out of  15n  + 8    as n tends to infinity

Lim n→∞  (n + 1)/ (15n + 8)  

Dividing numerator and denominator by n

=> Lim n→∞  (1 + 1/n)/ ( 15 + 8/n)  

=  ( 1 + 0)/(15 + 0)

=  1/15

In %  = 100/15  = 20/3  = 6.67 %

6.67 %  of 'S' are divisible by both 5 and 3

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