Question

sσlvє thє fσllσwíng:-
$1. \: p(8 - 2) = 12$
$2. \: ( - 5)(z + 2) = - 4$
$3. \: 6(k - 3) = 8$

Answer 1

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$1. \: p(8 - 2) = 12$

$\therefore p(6) = 12$

$\therefore p = 12 \div 6$

$\green \Longrightarrow \blue{\fbox{p = 2}}$

$2. \: ( - 5)(z + 2) = - 4$

$\therefore - 5z - 10 = - 4$

$\therefore - 5z = - 4 + 10$

$\therefore - 5z = 6$

$\green \Longrightarrow \blue{ \boxed{ z = - \frac{6}{5} }}$

$3. \: 6(k - 3) = 8$

$\therefore 6k - 18 = 8$

$\therefore 6k = 8 - 18$

$\therefore 6k = - 10$

$\therefore k = - \frac{10}{6}$

$\green \Longrightarrow \blue{ \boxed{ k = - \frac{5}{3} }}$

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Answer 2

$\Huge\bf{\color{maroon}{Solution:-}}$

$1. \bf \: p(8 - 2) = 12 \\ :\implies \bf p(6)=12 \\ :\implies \bf p=\dfrac{\cancel{12}^2}{\cancel 6}$

$2.\bf \: ( - 5)(z + 2) = - 4 \\ \bf :\implies z+2=\dfrac{4}{5} \\ :\implies\bf z=\dfrac{4}{5}-2 \\ :\implies\bf \dfrac{-12}{10}$

$3. \bf \: 6(k - 3) = 8 \\: \implies \bf k-3=\dfrac{8}{6} \\ :\implies\bf k=\dfrac{8}{6}+3 \\ :\implies\bf \dfrac{13}{3}$