➡ᴛᴡᴏ ᴘᴏʟᴇs ᴏғ ʜᴇɪɢʜᴛs 58 ᴍ ᴀɴᴅ 10 ᴍ sᴛᴀɴᴅ ᴜᴘʀɪɢʜᴛ ᴏɴ thᴇ ɢʀᴏᴜɴᴅ, ᴛʜᴇ ᴅɪsᴛᴀɴᴄᴇ ʙᴇᴛᴡᴇᴇɴ ᴛʜᴇᴍ ʙᴇɪɴɢ 14 m ғɪɴᴅ ᴛʜᴇ ʟᴇɴɢᴛʜ ᴏғ ᴛʜᴇ ᴡɪʀᴇ sᴛʀᴇᴛᴄʜᴇᴅ ғʀᴏᴍ ᴛʜᴇ ᴛᴏᴘ ᴛᴏ ᴛʜᴇ ᴘᴏʟᴇ ᴏғ ᴏɴᴇ ᴘᴏʟᴇ ᴛᴏ ᴛʜᴇ ᴛᴏ ᴏғ ᴛʜᴇ ᴏᴛʜᴇʀ ᴘᴏʟᴇ
Answers
Answer :
- The length of the wire streched from one pole to another (i.e, from h₁ to h₂) = 50 m
Explanation :
Given :
- Height of the first pole, h₁ = 58 m
- Height of the second pole, h₂ = 10 m
- Distance between the two poles (i.e, h₁ and h₂), s₁ = 14 m
To find :
- The length of the wire streched from one pole to another (i.e, from h₁ to h₂) = ?
Knowledge required :
- Pythagoras theorem :
⠀⠀⠀⠀⠀⠀⠀⠀⠀h² = b² + p²⠀
Where,
- h = Hypotenuse
- b = Base
- p = Height
Solution :
Given the length of AD is 58 m and that of BC is 10 m.
So the length of DE will be the difference length of AD and length of BC.i.e,
⠀⠀⠀⠀⠀⠀⠀⠀⠀∴ DE = AD - BC⠀
By substituting the values in it, we get :
⠀⠀=> DE = 58 - 10
⠀⠀=> DE = 48
⠀⠀⠀∴ DE = 48 m
Therefore, the length of DE is 48 m.
Now by using the pythagoras theorem and substituting the values in it, we get :
⠀⠀=> h² = b² + p²
⠀⠀=> h² = 14² + 48²
⠀⠀=> h² = 196 + 2304
⠀⠀=> h² = 2500
⠀⠀=> h = √2500
⠀⠀=> h = 50
⠀⠀⠀∴ h = 50 m
Therefore,
- The length of the wire streched from one pole to another (i.e, from h₁ to h₂) = 50 m.
Answer:
Given :-
- Two poles of height 58 m and 10 m stand upright on the ground, the distance between them being 14 m.
To Find :-
- What is the length of the wire stretched from the top to the pole of one pole to the other pole.
Formula Used :-
By using Phythagorus Theorem, we know that,
☆ (Hypotenuse)² = (Base)² + (Height)² ☆
Solution :-
Given :
➛ AB = DC = 14 cm
We have to find the length of EB,
⇒ EB = 58 - 10
➠ EB = 48 m
Now, by using Phythagorus Theorem we have to find the length of AE,
↦ (AE)² = (AB)² + (EB)²
↦ (AE)² = (14)² + (48)²
↦ (AE)² = 196 + 2304
↦ (AE)² = 2500
↦ AE = √2500
➦ AE = 50 m
∴ The length of the wire stretched from the top to the pole of one pole to the other pole is 50 m .
