Question

ᴘʟs sᴏʟᴠᴇ ᴛʜɪs.....ᴅᴏɴᴛ sᴘᴀᴍ​

Answer 1

☆Answer☆

Given:-

ABCD is a quadrilateral

AB=CD

AB||CD

☆Construction ☆

Join A and C

☆Proof ☆

In quadrilateral ABCD

AB=CD and AB||CD

AC is transversal line

angle DCA and angle BAC ( Alternate angles)

In triangle DCA and triangle BAC

DC=AB ( given)

angle DCA = angle BAC

AC= AC ( common side )

triangle DAC congruent to triangle BAC (side angle side )

angle DAC = angle BCA

Similarly prove DA|| CB

Hence , It is a parallelogram...

Answer 2

Answer:

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Step-by-step explanation:

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