Physics, asked by Anonymous, 5 months ago


✯ᴘʟᴇᴀsᴇ ᴀɴsᴡᴇʀ ɪɴ ᴅᴇᴛᴀɪʟ
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Answered by Ïmpøstër
180

\huge \bf \underline{ \underline \orange{answer : }} \:

Let the relation of the thermal conductivity and the temperature

K1A1(300−T)L1(steel)

=K2A2(T−0)L2(copper)

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Given :-

A1=2

A2=1

L1=15.0 cm

L2=10.0 cm

K1=50.2 J/smK

K2=385J/smK

▬▬▬▬▬▬▬▬▬▬▬

50.2×2×(300−T)/15 =385T/10

Temperature = 44.4 C°

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