Question

ᴘʟᴇᴀsᴇ sᴏᴍᴇᴏɴᴇ sᴏʟᴠᴇ ᴛʜɪs ǫᴜᴇsᴛɪᴏɴ
ɪᴛ's ᴠᴇʀʏ ᴠᴇʀʏ ɪᴍᴘᴏʀᴛᴀɴᴛ

The equation 2x²-12x+7 = 0 is written in the form 2(x-p)²+q = 0. what is the value of q ? ​​​

Answer 1

Step-by-step explanation:

ɢɪᴠᴇɴ ᴘᴏʟʏɴᴏᴍɪᴀʟ => x² - ᴘx + Q = 0

ʟᴇᴛ , ᴀ = 1 ; ʙ = - ᴘ ; ᴄ = Q

ᴡᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ,

ꜱᴜᴍ ᴏꜰ ᴛʜᴇ ʀᴏᴏᴛꜱ = - ʙ/ᴀ

→ ᴍ + ɴ = - (- ᴘ)/1 = ᴘ

ᴀɴᴅ,

ᴘʀᴏᴅᴜᴄᴛ ᴏꜰ ᴛʜᴇ ʀᴏᴏᴛꜱ = ᴄ/ᴀ

→ ᴍɴ = Q/1 = Q

ᴀ) ᴍ² + ɴ² ᴄᴀɴ ʙᴇ ᴡʀɪᴛᴛᴇɴ ᴀꜱ (ᴍ + ɴ)² - 2ᴍɴ

ɪ.ᴇ., ᴍ² + ɴ² + 2ᴍɴ - 2ᴍɴ.

→ ᴍ² + ɴ² = (ᴘ)² - 2(Q)

→ ᴍ² + ɴ² = ᴘ² - 2Q

ʙ) ᴍ^(- 1) = 1/ᴍ ᴀɴᴅ ɴ^(- 1) = 1/ɴ

ᴛᴀᴋɪɴɢ ʟᴄᴍ,

1/ᴍ + 1/ɴ = (ɴ + ᴍ)/ᴍɴ

→ (ᴍ + ɴ)/ᴍɴ

ᴘᴜᴛᴛɪɴɢ ᴠᴀʟᴜᴇꜱ,

→ ᴘ/Q

→ ᴍ^(- 1) + ɴ^(- 1) = ᴘ/Q

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘꜱ ᴜʜ...ᴍᴀʀᴋ ᴍᴇ ᴀꜱ ʙʀᴀɪɴɪᴇꜱᴛ ᴘʟᴢ..!!

$Thank \: uh..➰$

Answer 2

Answer:

hiii

Step-by-step explanation:

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