Question

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Answer 1

Answer:

1st:-

ANS:-5%

Step-by-step explanation:

SIMPLE INTEREST =PNR/100

Given,

P=630 ,N=4years,I=RS.126

So 126=630*4*R/100

.

. . R=5%

Hope it helped you!!!!

Answer 2

$\huge\bold\red{Question:-}$

(I) At what rate percent per annum will be ₹630 produce an interest of ₹126 in 4 years?

$\huge\bold\blue{Answer:-}$

Principal(P) = ₹630

Interest(I) = ₹126

Time(T) = 4years

Rate(R) = ?

As we Know,

I = $\dfrac{P×R×T}{100}$

Then,

R = $\dfrac{1\times100}{P×T}$

= $\dfrac{126\times100}{630\times4}$

= $\dfrac{100}{120}$

= 5%

$\quad$

$\huge\bold\red{Question:-}$

(II) At what rate percent per year will a sum double itself in $6\dfrac{1}{4}$ years?

$\huge\bold\blue{Answer:-}$

$\:$

Let Principal(P) = ₹100

$\therefore$ Amount = ₹(2×100) = ₹200

Interest = A - P = ₹ (200-100) = ₹100

T = $6\dfrac{1}{4}$ years=$\dfrac{25}{4}$ years

R =

$= \frac{100 \times 1}{p \times t} \\ = \frac{100 \times 100}{100 \times \frac{25}{4} } \% \\ = \frac{100 \times 100}{100} \times \frac{4}{25} = 16\%$