Question

ғᴏʀ ᴍᴀᴛʜs ᴀɴsᴡᴇʀᴇʀs!!

sɪᴍᴘʟɪғʏ ᴛʜᴇ ғᴏʟʟᴏᴡɪɴɢ :-

$(2 + \sqrt{2} ) + \frac{1}{(2 + \sqrt{2)} } + \frac{1}{ \sqrt{(2} - 2)}$

Thanks!!!

Answer 1

Answer: 2

Step-by-step explanation:

$Given : 2 + \sqrt{2} + \frac{1}{2+ \sqrt{2} } + \frac{1}{\sqrt{2}-2 } = (2 + \sqrt{2}) + [(\frac{1}{2+ \sqrt{2} }) - (\frac{1}{2 - \sqrt{2} }) ]= (2 + \sqrt{2} ) + [\frac{2 - \sqrt{2} -  (2 + \sqrt{2}) }{(2 + \sqrt{2})(2 - \sqrt{2})  } ]= 2 + \sqrt{2}  + \frac{(-2\sqrt{2}) }{2}= 2 + \sqrt{2}  - \sqrt{2} </p><p>= 2$

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Amrit

Answer 2

Step-by-step explanation:

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