ᴡʜᴀᴛ ɪs ᴛʜᴇ sᴛᴀɴᴅᴀʀᴅ ғᴏʀᴍ ᴏғ ᴛʜᴇ ᴘᴏʟʏɴᴏᴍɪᴀʟ
ᴛʜᴏsᴇ ᴡʜᴏ ᴋɴᴏᴡs ᴀɴsᴡᴇʀ ᴛʜᴇʏ ᴡɪʟʟ ᴏɴʟʏ ᴀɴsᴡᴇʀ ᴅᴏɴ'ᴛ sᴘᴀᴍ ᴀɴᴅ ᴡʀᴏɴɢ ᴀɴsᴡᴇʀ ᴡɪʟʟ ʙᴇ ʀᴇᴘᴏʀᴛᴇᴅ ᴀɴᴅ ᴘʟᴇᴀsᴇ ɢɪᴠᴇ sᴛᴇᴘ ʙʏ sᴛᴇᴘ ᴇxᴘʟᴀɴᴀᴛɪᴏɴ...
Answers
Answer:
The price of a smartphone is 5000 more than the cost of two feature phones &
the cost of 4 feature phones and two smartphone is 88,000 .
Exigency To Find : The cost of a smartphone and a feature phone.
⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀
❍ Let's Consider the cost price of smart phone and feature phone be Rs. x & Rs. y , respectively .
⠀⠀⠀⠀⠀⠀CASE I : The price of a smartphone is Rs. 5000 more than the cost of two feature phones .
\begin{gathered}\qquad :\implies \sf x = 2y + 5000 \:\:\\\end{gathered}
:⟹x=2y+5000
\begin{gathered}\qquad :\implies \bf x = 2y + 5000 \:\:\:\qquad\qquad \bigg\lgroup \sf{ Eq^n \: 1 }\bigg\rgroup\\\end{gathered}
:⟹x=2y+5000
⎩
⎪
⎪
⎪
⎧
Eq
n
1
⎭
⎪
⎪
⎪
⎫
⠀⠀⠀⠀⠀⠀CASE II : The cost of 4 feature phones and two smartphones is Rs. 88,000 .
\begin{gathered}\qquad :\implies \sf 4y + 2x = 88000 \:\:\\\end{gathered}
:⟹4y+2x=88000
\begin{gathered}\qquad :\implies \bf 4y + 2x = 88000 \:\:\:\qquad\qquad \bigg\lgroup \sf{ Eq^n \: 2}\bigg\rgroup\\\end{gathered}
:⟹4y+2x=88000
⎩
⎪
⎪
⎪
⎧
Eq
n
2
⎭
⎪
⎪
⎪
⎫
⠀⠀⠀⠀⠀⠀Now , Finding the cost of Smart phone & Feature phone :
\begin{gathered}\qquad \:\maltese\:\bf{ From \:Equation \:2 \:\::}\\\end{gathered}
✠FromEquation2:
\begin{gathered}\qquad \dag\:\:\bigg\lgroup \sf{Equation \:2\:: 4y + 2x = 88000 }\bigg\rgroup \\\\\end{gathered}
†
⎩
⎪
⎪
⎪
⎧
Equation2:4y+2x=88000
⎭
⎪
⎪
⎪
⎫
\begin{gathered}\qquad :\implies \sf 4y + 2x = 88000 \:\:\\\end{gathered}
:⟹4y+2x=88000
⠀⠀⠀⠀⠀⠀\begin{gathered}\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: Eq^n\:1 \: : \::}}\\\end{gathered}
⋆NowBySubstitutingtheEq
n
1::
\begin{gathered}\qquad \dag\:\:\bigg\lgroup \sf{Equation \:1\:: x = 2y + 5000 }\bigg\rgroup \\\\\end{gathered}
†
⎩
⎪
⎪
⎪
⎧
Equation1:x=2y+5000
⎭
⎪
⎪
⎪
⎫
\begin{gathered}\qquad :\implies \sf 4y + 2x = 88000 \:\:\\\end{gathered}
:⟹4y+2x=88000
\begin{gathered}\qquad :\implies \sf 4y +2 (2y + 5000) = 88000 \:\:\\\end{gathered}
:⟹4y+2(2y+5000)=88000
\begin{gathered}\qquad :\implies \sf 4y +4y + 10000 = 88000 \:\:\\\end{gathered}
:⟹4y+4y+10000=88000
\begin{gathered}\qquad :\implies \sf 4y +4y = 88000 - 10000 \:\:\\\end{gathered}
:⟹4y+4y=88000−10000
\begin{gathered}\qquad :\implies \sf 8y = 88000 - 10000 \:\:\\\end{gathered}
:⟹8y=88000−10000
\begin{gathered}\qquad :\implies \sf 8y = 78000 \:\:\\\end{gathered}
:⟹8y=78000
\begin{gathered}\qquad :\implies \sf y = \dfrac{ 78000}{8} \:\:\\\end{gathered}
:⟹y=
8
78000
\begin{gathered}\qquad :\implies \sf y = \cancel {\dfrac{ 78000}{8}} \:\:\\\end{gathered}
:⟹y=
8
78000
\begin{gathered}\qquad :\implies \bf y = 9750 \:\:\\\end{gathered}
:⟹y=9750
\begin{gathered}\qquad :\implies \frak{\underline{\purple{\:y = Rs.\: 9750 }} }\:\:\bigstar \\\end{gathered}
:⟹
y=Rs.9750
★
⠀⠀⠀⠀⠀⠀\begin{gathered}\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: \: Value\:of\: y \ [ \ 9750 \ ] \:in \:Eq^n \:1 \::}}\\\end{gathered}
⋆NowBySubstitutingtheValueofy [ 9750 ]inEq
n
1:
\begin{gathered}\qquad \dag\:\:\bigg\lgroup \sf{Equation \:1\:: x = 2y + 5000 }\bigg\rgroup \\\\\end{gathered}
†
⎩
⎪
⎪
⎪
⎧
Equation1:x=2y+5000
⎭
⎪
⎪
⎪
⎫
\begin{gathered}\qquad :\implies \sf x = 2y + 5000 \:\:\\\end{gathered}
:⟹x=2y+5000
\begin{gathered}\qquad :\implies \sf x = 2(9750) + 5000 \:\:\\\end{gathered}
:⟹x=2(9750)+5000
\begin{gathered}\qquad :\implies \sf x = 19500 + 5000 \:\:\\\end{gathered}
:⟹x=19500+5000
\begin{gathered}\qquad :\implies \bf x = 24500 \:\:\\\end{gathered}
:⟹x=24500
\begin{gathered}\qquad :\implies \frak{\underline{\purple{\:x \:= Rs.\: 24500 }} }\:\:\bigstar \\\end{gathered}
:⟹
x=Rs.24500
★
Therefore,
The cost of smartphone is : x = Rs. 24, 500
The cost of feature phone: y = Rs. 9,750
Therefore,
⠀⠀⠀⠀⠀\begin{gathered}\qquad \therefore {\underline{ \sf \:Cost \:of\:Smartphone \:and \:feature \:phone \:are\:\bf Rs. \ 24,500 \:\& \: Rs.\: 9,750\:\:\sf , \ respectively . }}\\\end{gathered}
∴
CostofSmartphoneandfeaturephoneareRs. 24,500&Rs.9,750, respectively.
⠀
Answer:
^rr~* vFkok ^; q"en* 'kCn ds pr qFkh Z foHkfDr d s ,dopu dk
:i fyf[k,A