Math, asked by trupthi8, 5 hours ago

ɴᴏ sᴘᴀᴍs !

ᴇxᴘʟᴀɴᴀᴛɪᴏɴ ɴᴇᴇᴅᴇᴅ !​

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Answered by user0888
6

Multiply \dfrac{ab}{ab}, which is one, to the number.

\text{L.H.S}=\dfrac{a^{-1}}{a^{-1}+b^{-1}}+\dfrac{a^{-1}}{a^{-1}-b^{-1}}

=\dfrac{ab}{ab} (\dfrac{a^{-1}}{a^{-1}+b^{-1}}+\dfrac{a^{-1}}{a^{-1}-b^{-1}})

=\dfrac{b}{b+a} +\dfrac{b}{b-a}

After taking the LCM of the denominator,

=\dfrac{b(b-a)}{(b+a)(b-a)} +\dfrac{b(a+b)}{(b+a)(b-a)}

=\dfrac{b^{2}-ab}{b^{2}-a^{2}} +\dfrac{b^{2}+ab}{b^{2}-a^{2}}

=\dfrac{b^{2}-ab+b^{2}+ab}{b^{2}-a^{2}}

=\dfrac{2b^{2}}{b^{2}-a^{2}}

=\boxed{-\dfrac{2b^{2}}{a^{2}-b^{2}} }

Answered by koppishettygreeshma
2

Step-by-step explanation:

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