Question

S-T=3 S/3+T/2=6 any body can solve this​

Answer 1

S - T = 3 ---- ( i ) and S / 3 + T /2 = 6 ---- ( ii )

On multiplying ( ii ) by 6 , we get

6 × S / 3 + 6 × T / 2 = 6 × 6

=> 2S + 3T = 36 ---- ( iii )

from ( i ) , S = 3 + T ---- ( iv ) , putting the value of S in eq. ( iii ) gives

2 ( 3 + T ) + 3T = 36

=> 6 + 2T + 3T = 36

=> 5T = 30

=> T = 6 , On putting in eq. ( iv ) gives

S = 3 + 6 = 9

Thus , S = 9 and T = 6

Answer 2

Answer:-

$\boxed{\sf{s=9}}\;or\;\boxed{\sf{t=6}}$

${\bf{\underline{Given:-}}}$

$\sf{s-t=3\;\;\;\;\;\;\;\;......(eq-1)}\\ \\ \sf{\frac{s}{3}+\frac{t}{2}=6\;\;\;\;\;\;.......(eq-2)}$

${\bf{\underline{Solution:-}}}$

$\sf{As\;s-t=3}$

$\sf{\implies s = t+3}$

$\sf{Subsituting\;the\;value\;of\;s\;in\;equation\;(2),}$

$\sf{\implies \frac{s}{3}+\frac{t}{2}=6}$

$\sf{\implies \frac{(t+3)}{3}+\frac{t}{2}=6}$

$\sf{\implies \frac{t}{3}+\frac{3}{3}+\frac{t}{2}=6}$

$\sf{\implies \frac{t}{3}+\frac{t}{2}+1=6}$

$\sf{\implies \frac{3t-2t}{6}=6-1}$

$\sf{\implies \frac{5t}{6}=5}$

$\sf{\implies 5t = 30}$

$\sf{\implies t = \frac{30}{5}=6}$

$\sf{Therefore,\;t=6}$

$\sf{Put\;the\;value\;of\;t\;in\;equation\;(1)}$

$\sf{\implies s-t=3}$

$\sf{\implies s-6=3}$

$\sf{\implies s=9}$

$\sf{Therefore\;s=9\;and\;t=6}$