Question

S team at an initial enthalpy of 100 kj/kg and inlet velocity of 100 m/s, enters an insulated horizontal nozzle. It leaves the nozzle at 200 m/s. The exit enthalpy (in kj/kg) is

Answer 1

Explanation:

Given Steam at an initial enthalpy of 100 kj/kg and inlet velocity of 100 m/s, enters an insulated horizontal nozzle. It leaves the nozzle at 200 m/s. The exit enthalpy (in kj/kg) is

• Given Initial enthalpy h1 = 100 kj / kg  
• Initial velocity V1 = 100 m/s (as it enters the nozzle)
• Final velocity V2 = 200 m/s (as it leaves the nozzle)
• Now we need to find h2
• Using the relation we have
• h1 + V1^2 / L = h2 + V2^2/L
• h2 = h1 + V1^2 / 2 – V2^2 / 2
•     = h1 + V1^2 – V2^2 / 2
•     = 100 x 10^3 + (100^2 – 200^2) / 2
•     = 200 x 10^3 + (10000 – 40000) / 2
•    = 2,00,000 – 30,000 / 2
•     = 1,70,000 / 2
•     = 85 x 10^3 J/Kg
•     = 85 kJ /kg

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https://brainly.in/question/34775624