Question

s10=150,s9=126,find t10​

Answer 1

Answer:

T10=24

Step-by-step explanation:

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Answer 2

Answer:

S=(n/2)(2a+(n-1)d)

S10=5(2a+9d)

150=5(2a+9d)

150/5=30=(2a+9d)

30=(2a+9d).... (1)

S9=9/2(2a+8d)

126=9/2(2a+8d)

126*2/9=30=(2a+8d)

28=2a+8d......(2)

Subtract 2 from 1

2=d

a=28-8d/2=28-16/2=12/2=6

t10=a+9d=6+9(2)=6+18=24