S10 in an ap if the sum of first 3 term is 9 and sum of next 3 term is 27 is
a)30
b)38
c)46
d)36
Answers
Answered by
7
Answer:
the answer is 38
Step-by-step explanation:
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Answered by
0
Step-by-step explanation:
Let the terms of AP be a-5d, a-3d, a-d, a+d, a+3d, a+5d
Sum of first 3 terms
3a-9d=9
a-3d=3
Sum of next 3 terms
3a+9d=27
a+3d=9
Solving both equations,
a=6, d=1
Now S10 = n/2 (2a + (n-1) d)
S10 = 5 (12 + (9). 1)
S10 = 5 (21)
S10 = 105
Verification
a=6, d=1
Terms are 6,7,8,9,10,11,12,13,14,15
If you add the terms you will get 105.
It is my answer
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