S17 -S16 =.................. answer to this question
atharvvtiwari:
It'll be equal to a17, i.e. the 17th term of the series
Answers
Answered by
44
S17 = 17/2 * (2a + 16d)
17*(a + 8d)
17a + 136d
S16 = 16/2 * (2a + 15d)
8* (2a + 15d)
16a + 120d
S17- S16 = 17a +136d - 16a - 120d
a + 16d = a17
S17- S16 = a17
Answered by
1
Answer:
Hope it helps you mate..
Attachments:
Similar questions