S2, if x is irrational
2. If fis defined on R as f (x) =
1, if x is rational,
lim
f(x) does not exist for any a € R.
X ->a
prove that
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Answer:
ANSWER
At x=0
x→0
+
lim
f(x)=0
(Same for rational and irrational)
Also
x→0
−
lim
f(x)=0
So it is continuous at x=0
At other number it's limit is not defined in it's neighbourhood as it can be x or 0 when x
=0 it is not continuous.
So f(x) is continuous only at 0
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