Question

S30 = 3(s20-s10)

THIS some is of Arthematic progression
this is a proving sum please write statement

Answer 1

Here's the answer. I hope this helps.

Answer 2

S30= (30/2)[2(a)+(n-1)d]
=15[2a+(n-1)d] ..... (1)

S20=(20/2)[2a+(n-1)d]
=10[2a+(n-1)d].........(2)

S10=(10/2)[2a+(n-1)d]
=5[2a+(n-1)d].........(3)

Subtracting eqn (2) by (3)

S20-S10= 5[2a+(n-1)d]......(4)


Multiply equation (4) by 3.

You'll get LHS=RHS.

Hence proved

(If this helped you please my answer as brainliest if you want. thanks , have a good day/night)