Question

S8+O2-SO2 Find out mass of S8 required to produce 128g of SO2 if % yeild of the reaction is 80%

Answer 1

Answer:

Explanation:

2.5g

2SO  

2

​

+O  

2

​

→SO  

3

​

 

Here the mole ratio between S0  

2

​

 and SO  

3

​

 is 2:2 = 1.

Here we used 2 g of SO  

2

​

, so we need to convert that amount into moles.

Sulphur dioxide has molar mass of 64 g/mol. So,

64g/mol

2g

​

 = 0.03125 mol of SO  

2

​

 

Sulphur trioxide has molar mass of 80 g/mol. So,

0.03125 mol. 80 g/mol = 2.5 g of SO  

3

​

 

Sp, 2.5 grams of sulphur trioxide was produced.

Answer 2

Answer:

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Explanation:

this is the photot of the answer