Question

SA
H(Z=1) 1s
He(Z=2) 1s?
11
1 l
1
Li(Z=3) 1s 2s
Be(Z=4) 1s22s?
1 !
B(Z=5) 1s²2s22p!
1​

Answer 1

Answer:

What is this??? I do not understand ur question

Answer 2

Answer:

ANSWER

The number of sub energy levels →n

The number of orbitals in sub energy levels →2l+1

The number of orbitals in energy level →n

2

For 3d we have,[l=0,1....n,m=−2,−1,0,+1,+2]

n=3,l=2 for orbital

Thus,

n=3,l=2,m=0→3d orbital

Option A is correct.

Explanation:

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