सिद्ध कीजिए कि 5-{3}{7}√3 एक अपरिमेय संख्या है
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Step-by-step explanation:
Given Prove that 5- {3} {7} √3 is an irrational number
- We need to prove that 5 – 3 / 7√3 is an irrational number.
- Also we need to write in p/q form where p and q are co prime.
- So 5 – 3 / 7√3 = p/q
- Or 5 – p/q = 3 / 7√3
- Or 5q – p / q = 3 / 7√3
- 3q / 5q – p = 7√3
- 3q / 7(5q – p) = √3
- Therefore the left hand side is a rational number and the right hand side is an irrational number which cannot be equal and so it contradicts the assumption.
- Therefore 5 – 3/7√3 is an irrational number.
Reference link will be
https://brainly.in/question/6310502
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