Question

Sachin can cover a distance in 1 hr 24 min by covering 2/3 of the distance at 4 kmph and the rest at 5 kmph. the total distance is?

Answer 1

2.5km will be the total distance

Answer 2

Answer:

6 km

Step-by-step explanation:

Let total distance =D

Distance travelled at 4 kmph speed :

$= \left(\dfrac{2}{3}\right)D$

Since he travelled rest at 5 kmph

So, Distance travelled at 5 kmph speed :

$= \left(1-\dfrac{2}{3}\right)D = \left(\dfrac{1}{3}\right)D$

Total time =1 hr 24 min = (60+24) min $=\dfrac{84}{60}$$= \dfrac{21}{15}$

Since we know that

$\text{Time}=\dfrac{\text{Distance}}{\text{Speed}}$

So, Total time :$\dfrac{21}{15}=\dfrac{2/3}{4}D+\dfrac{1/3}{5}D$

$\dfrac{21}{15}=\dfrac{2D}{12}+\dfrac{D}{15}$

$84=14D$

$D= \textbf{6 km}$

Hence the total distance is 6 km