Math, asked by kavaliramkumar999, 10 months ago


Saket and Swamy rent a pasture for 10
months. Saket puts in 80 oxen for 7 mont
How many can Swamy put in for the
remaining 3 months ? He pays 11212 time
of Saket.
280 days
240 days
250 days
300 days​

Answers

Answered by amitnrw
0

Given :  Saket and Swamy rent a pasture for 10  months. Saket puts in 80 oxen for 7 mont h. Swami pays 1 1/2 times of Saket

To find :  How many can Swamy put in for the  remaining 3 months

Solution:

Saket and Swamy rent a pasture for 10

months. Saket puts in 80 oxen for 7 month

=> Total effective oxen = 7 * 80  = 560

Swamy pays  1 1/2   (1.5) times  of Saket

hence Swami can put effctive oxen = 560 * (3/2)  =  840   oxen

But swami has 3 months only

Hence swami Can put Each month = 840/3 =  280 oxen

Swamy can put in 280 oxen for the  remaining 3 months

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