Saktiman covered a total distance of 670 km by travelling 9 hours by bus and 4 hours by
taxi meanwhile Arjun travelled 7 hours by taxi and 8 hours by bus covering a distance of
785 km. Find the speed of the taxi and the bus if the speeds of the 2 buses were same and
the speeds of both taxi are same
Answers
Answer:
The Speed of the bus = 50 kmph
The Speed of the taxi = 55 kmph
Step-by-step explanation:
Given;
Speed of the two Taxis are equal;
And Speed of the two Buses are equal.
Let the Speed of the Bus = S1
Let the Speed of the Taxi = S2
Saktiman:
The distance covered by Saktiman () = 670 km
He used two means of transport.
1 = Speed of the bus x Time
= S1 x 9
2 = Speed of the taxi x Time
= S2 x 4
= 1 + 2
=> 9S1 + 4S2 = 670 ------- Eq(1)
Arjun:
The distance covered by Arjun () = 785 km
He used two means of transport.
1 = Speed of the Taxi x Time
= S2 x 7
2 = Speed of the Bus x Time
= S1 x 8
= 1 + 2
=> 8S1 + 7S2 = 785 ------- Eq(2)
Solving Eq(1) & Eq(2):
9S1 + 4S2 = 670 x 7
8S1 + 7S2 = 785 x 4
63S1 + 28S2 = 4690
32S1 + 28S2 = 3140
(-) (-) (-)
------------------
31S1 = 1550
=> S1 = 50 km/hr
From Eq(2);
8S1 + 7S2 = 785
8(50) + 7S2 = 785
=> 7S2 = 785 - 400
=> 7S2 = 385
=> S2 = 55 km/hr
Therefore,
The Speed of the bus S1 = 50 kmph
The Speed of the taxi S2 = 55 kmph
Answer:
The Speed of the bus X= 50 kmph
The Speed of the taxi Y = 55 kmph
Step-by-step explanation:
In this question
We have been given that
Speed of the two Taxis are equal;
And Speed of the two Buses are equal.
Let the Speed of the Bus = X
Let the Speed of the Taxi = Y
Saktiman:
The distance covered by Saktiman = 670 km
He used two means of transport.
Distance Covered by bus = Speed of the bus x Time
= X x 9
Distance covered by taxi = Speed of the taxi x Time
= Y x 4
Total Distance
=> 9X + 4Y = 670 -------(i)
Arjun:
The distance covered by Arjun = 785 km
He used two means of transport.
Distance covered by Taxi = Speed of the Taxi x Time
= Y x 7
Distance covered by Bus = Speed of the Bus x Time
= X x 8
Total Distance covered
=> 8X + 7Y = 785 ------- (ii)
Solving (i) & Eq(ii) we get:
9X + 4Y = 670
8X + 7Y = 785
On solving for X and Y we get,
=> X = 50 km/hr
From (ii) we get;
8X + 7Y = 785
8(50) + 7Y = 785
=> 7Y = 785 - 400
=> 7Y = 385
=> Y = 55 km/hr
Therefore,
The Speed of the bus X= 50 kmph
The Speed of the taxi Y = 55 kmph