Question

Sally has 2 cats and eat cat eats 1/4 of a n of cat food each day sally buys 9 tins of cat food
For how many days will the cat food feed her 2 cats?

Answer 1

Answer:

Sally has 2 cats

food eaten by 1 cat each day = \frac{1}{4}

4

1

food eaten by 2 cat each day= \frac{1}{4}\times 2 = \frac{1}{2}

4

1

×2=

2

1

tins

sally buys 9 tins of cat food

then

\frac{1}{2}

2

1

tins required in = 1 day

1 tin required in

\frac{1}{\frac{1}{2} }= 2

2

1

1

=2

i.e 1 tin required in 2 days

9 tin required for = 9×2 = 18 days

hence , 9 tins of cat food feed her 2 cats for 18 days

Step-by-step explanation:

hope it will help u

Answer 2

Sally has 2 cats

$food \: eaten \: by \: 1 \: cat \: each \: day = \frac{1}{4}$

food eaten by 2 cat each day=

$\frac{1}{4}\times 2 = \frac{1}{2} tins$

sally buys 9 tins of cat food

$\frac{1}{2} \: tins \: required \: in = 1 \: day$

1 tin required in

$\frac{1}{\frac{1}{2} }= 2$

i.e 1 tin required in 2 days

9 tin required for = 9×2 = 18 days

hence , 9 tins of cat food feed her 2 cats for 18 days