Math, asked by shreyaSingh2022, 3 months ago

Salmonpanna2022 please solve that question.
Only this question I am asking from Salmon.​

Attachments:

Answers

Answered by Salmonpanna2022
8

Step-by-step explanation:

पश्न:

 \sqrt{4 -  \sqrt{7} }   +  \sqrt{8 + 3 \sqrt{7} }  \\

उत्तर:

 \sqrt{2} ( \sqrt{7}  + 1)

 \sqrt{4 -  \sqrt{7} }  -  \sqrt{8 +  3\sqrt{7} }  \\  =  >  \sqrt{ \frac{(4 -  \sqrt{7}) \times 2 }{2} }  +  \sqrt{ \frac{(8 + 3 \sqrt{7})  \times 2 }{2} }  \\  =  >  \sqrt{ \frac{8 - 2 \sqrt{7} }{2} }   +  \sqrt{ \frac{16 + 6 \sqrt{7} }{2} }  \\  =  >  \sqrt{ \frac{( \sqrt{7})^{2} + 1 - 2 \sqrt{2}   }{2} }  \\  \sqrt{ \frac{( {3})^{2} +( \sqrt{7} ) ^{2}  + 2  \times 3 \times  \sqrt{7}   }{2} }   \\ =   >  \sqrt{ \frac{( { \sqrt{7 } - 1 )}^{2} }{2} }  +  \sqrt{ \frac{3 + ( { \sqrt{7} )}^{2} }{2} }  \\  =  >  \frac{ \sqrt{7}  - 1}{ \sqrt{2} }  +  \frac{3 +  \sqrt{7} }{ \sqrt{2} }  \\  =  >  \frac{ \sqrt{7}  - 1  + 3 +  \sqrt{7} }{ \sqrt{2} }  =  \frac{2 \sqrt{7} + 2 }{ \sqrt{2} }  \\  =  >  \frac{ \sqrt{2} ( \sqrt{2} \times  \sqrt{7}  +  \sqrt{2} ) }{ \sqrt{2} }  =  \sqrt{2} ( \sqrt{7}  + 1) \:  \: ans.

 { }^{i \: hope \: its \: help \: you.}

Similar questions