Question

salue for x, y =
2x=2^2*2^y
and
9*3^x=3^-y​

Answer 1

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ANSWER

Given

2x−

y

3

=9...(1)

3x+

y

7

=2...(2)

Let us use the elimination method to solve the given system of equation.

Multiply (1) by 3 and (2) by 2,We get

6x−

y

9

=27...(3)

6x+

y

14

=4...(4)

Now, subtracting equation (3) from(4)

(6x+

y

14

)−(6x−

y

9

)=4−27

⇒

y

14

+

y

9

=−23

⇒

y

23

=−23

⇒y=−1

Substitute the value of y in equation (1), we have

2x−

(−1)

3

=9

⇒2x+3=9

⇒2x=6

⇒x=3

Hence x=3,y=−1