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HERE'S YOUR QUESTION FOR THE DAY ⬇
What is the value of e^(π×i) ?
I WANT THE ANSWER WITH THE STEPS.
INCORRECT OR GOOGLE ANSWERS WILL BE REPORTED ;)
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Hello user☺☺
There is no any proper proof of this e^(π×i) . But there are assumptions that this might be equal to -1, ie..
e^(π×i) + 1 = 0
e^(π×i) = -1.
Since, e , pi and i are the most important constants of the mathematics and hence mathematicians have assumptions that these constantw together will form the most basic numbers of mathematics and that is the negative of unity = -1.
Since, pi and e are two irrational positive numbers and therefore you might will get wondered that how this came to a negative number but let me make toy aware of i which is an imaginary number and is equal to (-1)^1/2.
Here, all the general laws of exponent breaks and we cannot reach to a particular result.
There is no proper proof regarding this and is yet to be discovered.
Hope it works☺☺
There is no any proper proof of this e^(π×i) . But there are assumptions that this might be equal to -1, ie..
e^(π×i) + 1 = 0
e^(π×i) = -1.
Since, e , pi and i are the most important constants of the mathematics and hence mathematicians have assumptions that these constantw together will form the most basic numbers of mathematics and that is the negative of unity = -1.
Since, pi and e are two irrational positive numbers and therefore you might will get wondered that how this came to a negative number but let me make toy aware of i which is an imaginary number and is equal to (-1)^1/2.
Here, all the general laws of exponent breaks and we cannot reach to a particular result.
There is no proper proof regarding this and is yet to be discovered.
Hope it works☺☺
Anonymous:
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If u still use this app
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