Math, asked by parthusethi, 11 months ago

Sam has 3 identical squares. He places one square on top of 2 squares as shown in the figure. What is the area of the overlap?

Attachments:

Answers

Answered by vivekanand52
2

Area of overlap is 88 sq. cm.

Step-by-step explanation:

See the diagram attached.

The required area is the polygon ABCDE (The pink zone).

So, we have to deduct the area of the triangle Δ DEF (Yellow zone) from the total square i.e. ABCF.

Now, area of the overlap = (10 × 10) - 0.5 × 3 × (10 + 10 - 6 - 6)

= 100 - 0.5 × 3 × 8

= 100 - 12

= 88 sq. cm. (Answer)

Attachments:
Answered by technothepigg
0

Answer: (A) 88 cm^2

Step-by-step explanation:

As the side of each square is 10cm, the base of the triangle above the overlap = 4cm + 4cm = 8cm

Therefore, area of the triangle above the overlap

= 1/2 * 8 * 3 = 12cm^2

Hence, the area of the overlap

= Area of the square - area of the triangle above the overlap

= 100cm^2 - 12cm^2

= 88cm^2

Similar questions