sam of 3 consecutive integers '18'.so find the integer.
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X+(X+1)+(X+2)=18
3X+3=18
X=15/3
X=5
Therefore 5,6,7 is integers
3X+3=18
X=15/3
X=5
Therefore 5,6,7 is integers
Answered by
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let the integers be x,x+1,x+2
x+x+1+x+2=18
3x+3=18
3x=18-3
3x=15
x=15/3
x=5
one integer-x=5
second integer=x+1=6
third integer-x+2=7
hope it helps
plz mark as brainliest
x+x+1+x+2=18
3x+3=18
3x=18-3
3x=15
x=15/3
x=5
one integer-x=5
second integer=x+1=6
third integer-x+2=7
hope it helps
plz mark as brainliest
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