समान्तर श्रेणी 1, 4, 7, 10..... का कौन-सा पद 88 है ?
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2
Answer:
30
30 is correct answer
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Given AP is 1, 4, 7, 10,....
Here, t1 = a = 1
t2 = 4 d = 3
tn = 88
We have to find n
We know,
tn = a + (n-1) d
88 = 1 + (n-1) 3
88 = 1 + 3n - 3
88 = 3n - 2
3n = 88+2
3n = 90
n = 90/3
n = 30
88 is the 30th term of the given AP
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