Question

समलंब ABCD में कोण A= 100° तथा कोण B
= 110° हैं तब शेष दोनों कोणों की माप क्या होगी?​

Answer 1

Answer:

C=70 degree,D=80 degree

A+D=180(AB II CD and AD is the transversal.)

=>100+D=180

=>D=80

B+C=180(ABIICD and BC is the transversal)

=>110+C=180

=>C=70

Answer 2

m∠D = 80° and  m∠C = 70°

Step-by-step explanation:

Given,

In trepezoid ABCD,

m∠A = 100°, m∠B = 110°

In a trapezoid there is a pair of parallel sides also, the sum of adjacent angles by a same transversal on two parallel sides is 180°,

∵ m∠A + m∠B ≠ 180°,

So, AD can not be parallel to BC,

Thus, AB ║ CD,

By the above statement,

m∠A + m∠D = 180° and m∠B + m∠C = 180°

100° + m∠D = 180° and 110° + m∠C = 180°

m∠D = 180°-100° and m∠C = 180°-110°

m∠D = 80° and  m∠C = 70°

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