Question

Same mass of CH₄ and H₂ is taken in container, The partial
pressure caused by H₂ is
(a) 8/9
(b) 1/9
(c) 1/2
(d) 1

Answer 1

The partial pressure caused by H2 is 8/9.

Option (A) is correct.

Explanation:

Let the equal mass to be taken is 16 g .

Then no. Of moles of CH4 = 16/16 = 1

No. Of moles of H2 = 16/2 =8 ( no.of moles =given weight/molecular weight)

Then mole fraction of H2 = 8 / (8+1) = 8/9

Partial pressure caused by H2 = 8/9(total pressure)

As it is done in container so total pressure = 1 ATM

Partial pressure caused by H2 = 8/9×1 =8/9

Thus the partial pressure caused by H2 is 8/9.

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Answer 2

The partial  pressure caused by H₂ is $\bold{\frac{8}{9}}$

Step by step explanation:

The mass of gases =16g

Total pressure = 1 atm

Let's calculate the number of moles of each gas.

Number of moles of methane = $\frac{16}{16}=1$mol

Number of moles of hydrogen = $\frac{16}{2}=8$

Then, the mole fraction of $H_{2}=\frac{8}{8+1}$

                                                 $\Rightarrow \frac{8}{9}$

Partial pressure caused by $H_{2}=Total\,pressure\times \frac{8}{9}$

$Pressure\,caused\,by\,H_{2}=1\times \frac{8}{9}$

Therefore, The partial  pressure caused by H₂ is $\bold{\frac{8}{9}}$

Hence, correct option is "a".

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