Question

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Answer 1

Step-by-step explanation:

• Here,
• In ∆ABD and ∆CBD
• AB = CD (Given)
• AD = BC (Given)
• BD = BD (common)
• So, ∆ABD≈ ∆CBD
• Hence,Angle ABD = Angle CDB (by C. P. C. T.)

Answer 2

The parallelogram is divided into two triangle and we have to use showing SSS Criteria to prove angle acd = angle cdb . According to SSS criteria,
AB = DC ( Given )
BD = BD ( Common)
AD = BC (Given)

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