sample of 1 gram of aluminium are treated separately with an excess of sulphuric acid and an excess of sodium hydroxide the ratio of number of moles of hydrogen gas evolved is
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1) H2SO4 (excess)
2 Al + 3 H2SO4→Al2(SO4)3 + 3H2
2) NaOH(excess)
2 Al + 2NaOH + 2H2O → 2NaAlO2 + 3H2
Ratio of volumes of hydrogen evolved = 3:3 ie.1:1
2 Al + 3 H2SO4→Al2(SO4)3 + 3H2
2) NaOH(excess)
2 Al + 2NaOH + 2H2O → 2NaAlO2 + 3H2
Ratio of volumes of hydrogen evolved = 3:3 ie.1:1
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