Question

sample of monoatomic gas is at 20 degrees 8 if both the volume and pressure is doubled what will be its temperature now​

Answer 1

Answer:

$\frac{p1 \times v1}{t1} = \frac{p2 \times v2}{t2} \\ \frac{p1v1}{t1} = \frac{2p1 \times 2v1}{t2 } \\ \frac{1}{293} = \frac{4}{t2 } \\ t2 = 1172k \: or \: 899c$